%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : PUZ140^1 : TPTP v8.1.2. Released v6.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 13:14:52 EDT 2023

% Result   : Theorem 3.76s 3.99s
% Output   : Proof 3.76s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.14  % Problem    : PUZ140^1 : TPTP v8.1.2. Released v6.1.0.
% 0.10/0.15  % Command    : duper %s
% 0.16/0.37  % Computer : n021.cluster.edu
% 0.16/0.37  % Model    : x86_64 x86_64
% 0.16/0.37  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.37  % Memory   : 8042.1875MB
% 0.16/0.37  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.16/0.37  % CPULimit   : 300
% 0.16/0.37  % WCLimit    : 300
% 0.16/0.37  % DateTime   : Sat Aug 26 22:54:57 EDT 2023
% 0.22/0.37  % CPUTime    : 
% 3.76/3.99  SZS status Theorem for theBenchmark.p
% 3.76/3.99  SZS output start Proof for theBenchmark.p
% 3.76/3.99  Clause #0 (by assumption #[]): Eq (∀ (B : beverage), hot (heat B)) True
% 3.76/3.99  Clause #3 (by assumption #[]): Eq (Not (Exists fun Mixture => ∀ (S : syrup), Exists fun B => And (Eq (Mixture coffee S) B) (hot B))) True
% 3.76/3.99  Clause #4 (by clausification #[0]): ∀ (a : beverage), Eq (hot (heat a)) True
% 3.76/3.99  Clause #12 (by clausification #[3]): Eq (Exists fun Mixture => ∀ (S : syrup), Exists fun B => And (Eq (Mixture coffee S) B) (hot B)) False
% 3.76/3.99  Clause #13 (by clausification #[12]): ∀ (a : beverage → syrup → beverage), Eq (∀ (S : syrup), Exists fun B => And (Eq (a coffee S) B) (hot B)) False
% 3.76/3.99  Clause #14 (by clausification #[13]): ∀ (a : beverage → syrup → beverage) (a_1 : syrup),
% 3.76/3.99    Eq (Not (Exists fun B => And (Eq (a coffee (skS.0 0 a a_1)) B) (hot B))) True
% 3.76/3.99  Clause #15 (by clausification #[14]): ∀ (a : beverage → syrup → beverage) (a_1 : syrup),
% 3.76/3.99    Eq (Exists fun B => And (Eq (a coffee (skS.0 0 a a_1)) B) (hot B)) False
% 3.76/3.99  Clause #16 (by clausification #[15]): ∀ (a : beverage → syrup → beverage) (a_1 : syrup) (a_2 : beverage),
% 3.76/3.99    Eq (And (Eq (a coffee (skS.0 0 a a_1)) a_2) (hot a_2)) False
% 3.76/3.99  Clause #17 (by clausification #[16]): ∀ (a : beverage → syrup → beverage) (a_1 : syrup) (a_2 : beverage),
% 3.76/3.99    Or (Eq (Eq (a coffee (skS.0 0 a a_1)) a_2) False) (Eq (hot a_2) False)
% 3.76/3.99  Clause #18 (by clausification #[17]): ∀ (a : beverage) (a_1 : beverage → syrup → beverage) (a_2 : syrup),
% 3.76/3.99    Or (Eq (hot a) False) (Ne (a_1 coffee (skS.0 0 a_1 a_2)) a)
% 3.76/3.99  Clause #19 (by superposition #[18, 4]): ∀ (a : beverage → syrup → beverage) (a_1 : syrup) (a_2 : beverage),
% 3.76/3.99    Or (Ne (a coffee (skS.0 0 a a_1)) (heat a_2)) (Eq False True)
% 3.76/3.99  Clause #63 (by clausification #[19]): ∀ (a : beverage → syrup → beverage) (a_1 : syrup) (a_2 : beverage), Ne (a coffee (skS.0 0 a a_1)) (heat a_2)
% 3.76/3.99  Clause #64 (by equality resolution #[63]): False
% 3.76/3.99  SZS output end Proof for theBenchmark.p
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